Make parse_date accept several short forms.
Short forms are only accepted in interactive mode (e.g. when using the "Go to" function, editing a recurrent item's end date, and so on). Samples: "1/1/30" for "01/01/2030", "26" for the 26th of the currently selected month/year or "3/1" for Mar 01 (or Jan 03, depending on the date format) of the currently selected year.
This commit is contained in:
101
src/utils.c
101
src/utils.c
@@ -1,4 +1,4 @@
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/* $calcurse: utils.c,v 1.86 2010/11/04 10:55:07 fleischer Exp $ */
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/* $calcurse: utils.c,v 1.87 2011/01/11 22:10:48 fleischer Exp $ */
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/*
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* Calcurse - text-based organizer
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@@ -47,6 +47,8 @@
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#include "calcurse.h"
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#define isleap(y) ((((y) % 4) == 0 && ((y) % 100) != 0) || ((y) % 400) == 0)
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/* General routine to exit calcurse properly. */
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void
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exit_calcurse (int status)
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@@ -883,64 +885,81 @@ erase_note (char **note, enum eraseflg flag)
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/*
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* Convert a string containing a date into three integers containing the year,
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* month and day.
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*
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* If a pointer to a date structure containing the current date is passed as
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* last parameter ("slctd_date"), the function will accept several short forms,
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* e.g. "26" for the 26th of the current month/year or "3/1" for Mar 01 (or Jan
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* 03, depending on the date format) of the current year. If a null pointer is
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* passed, short forms won't be accepted at all.
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*
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* Returns 1 if sucessfully converted or 0 if the string is an invalid date.
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*/
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int
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parse_date (char *date_string, enum datefmt datefmt, int *year, int *month,
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int *day)
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int *day, struct date *slctd_date)
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{
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int in1, in2, in3;
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int lyear, lmonth, lday;
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char sep = (datefmt == DATEFMT_ISO) ? '-' : '/';
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char *p;
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int in[3] = {0, 0, 0}, n = 0;
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int d, m, y;
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if (date_string == 0)
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return 0;
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if (!date_string) return 0;
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if (datefmt == DATEFMT_ISO)
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{
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if (sscanf (date_string, "%d - %d - %d", &in1, &in2, &in3) < 3)
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return 0;
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/* parse string into in[], read up to three integers */
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for (p = date_string; *p; p++) {
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if (*p == sep) {
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if ((++n) > 2) return 0;
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}
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else
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{
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if (sscanf (date_string, "%d / %d / %d", &in1, &in2, &in3) < 3)
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return 0;
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else if ((*p >= '0') && (*p <= '9')) {
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in[n] = in[n] * 10 + (int)(*p - '0');
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}
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switch (datefmt)
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{
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else
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return 0;
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}
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if ((!slctd_date && n < 2) || in[n] == 0) return 0;
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/* convert into day, month and year, depending on the date format */
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switch (datefmt) {
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case DATEFMT_MMDDYYYY:
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lmonth = in1;
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lday = in2;
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lyear = in3;
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m = in[n > 0 ? 0 : 1];
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d = in[n > 0 ? 1 : 0];
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y = in[2];
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break;
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case DATEFMT_DDMMYYYY:
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lday = in1;
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lmonth = in2;
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lyear = in3;
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d = in[0];
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m = in[1];
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y = in[2];
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break;
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case DATEFMT_YYYYMMDD:
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case DATEFMT_ISO:
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lyear = in1;
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lmonth = in2;
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lday = in3;
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case DATEFMT_ISO:
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y = in[0];
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m = in[n - 1];
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d = in[n];
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break;
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default:
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return 0;
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}
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if (lyear < 1 || lyear > 9999
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|| lmonth < 1 || lmonth > 12
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|| lday < 1 || lday > 31)
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}
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if (y > 0 && y < 100) {
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/* convert "YY" format into "YYYY" */
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y += slctd_date->yyyy - slctd_date->yyyy % 100;
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}
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else if (n < 2) {
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/* set year and, optionally, month if short from is used */
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y = slctd_date->yyyy;
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if (n < 1) m = slctd_date->mm;
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}
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/* check if date is valid, take leap years into account */
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if (y < 1902 || y > 2037 || m < 1 || m > 12 || d < 1 ||
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d > days[m - 1] + (m == 2 && isleap (y)) ? 1 : 0)
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return 0;
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if (year != NULL)
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*year = lyear;
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if (month != NULL)
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*month = lmonth;
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if (day != NULL)
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*day = lday;
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if (year) *year = y;
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if (month) *month = m;
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if (day) *day = d;
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return 1;
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}
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